[erekose]

WOW!

Thats a puzzle, and it's hard to think how they're going to make one harder than that. Tempting to try to solve though...

(erekose puts puzzle on list of things to do, right after 'formulate Unified Field Theory')

On second thought, given this puzzle, asking us to solve the holy grail of physics would be easy.

[JebJoya]

WHAT THEflippity floo?!

I joked about this being a card on IRC last night. This is being researched by hundereds of mathematicians all over the world, for a good popular science (readable maths) book on it, try "Dr. Riemann's Zeros" by Karl Sabbagh.

Right, for some more detail:

sum to infinity (1/n^s)

so 1/(1^s) + 1/(2^s) +....

n^s = n^(p+qi) = (n^p)(n^qi)

= (n^p) * (e^ (qi*ln(n)))

and then to take 1/(n^s) = n^(-s)

= (n^-p) * (e^(-qi*ln(n)))

so we've got to find the sum (n->inf) of the above equation, and prove that this can only equal 0 if p=(1/2) (that's minus a couple of special cases, i believe...)

of course, here we have re^(i*theta), which creates a vector in an argand diagram, which of course you can add to by adding nose to tail of the vectors. The length of the vector is (n^-p), and the direction of the vector is (-qi*ln(n)) radians.

That's some junk to look at

Jeb

EDIT - uhhhh, changed two words so that they weren't quite as glaringly... swearlike... - SG

[Flidget Jerome]

And all I can think is "Take that, Where.gif!"

[dusty2229]

Not quite sure what this is asking us to do
BTW it's worth a mere 60 points

[cassandra]

And exactly how many Perplex City points is this one worth?

[Flidget Jerome]

Is that asking us to solve what I think it's asking us to solve? It looks pretty straight forward, but also insane.

[dusty2229]

 [Puzzle] Silver #238 Riemann